1d^2+2d+80=

Solution for 1d^2+2d+80= equation:

Simplifying
1d2 + 2d + 80 = 0

Reorder the terms:
80 + 2d + 1d2 = 0

Solving
80 + 2d + 1d2 = 0

Solving for variable 'd'.

Begin completing the square.

Move the constant term to the right:

Add '-80' to each side of the equation.
80 + 2d + -80 + d2 = 0 + -80

Reorder the terms:
80 + -80 + 2d + d2 = 0 + -80

Combine like terms: 80 + -80 = 0
0 + 2d + d2 = 0 + -80
2d + d2 = 0 + -80

Combine like terms: 0 + -80 = -80
2d + d2 = -80

The d term is 2d.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2d + 1 + d2 = -80 + 1

Reorder the terms:
1 + 2d + d2 = -80 + 1

Combine like terms: -80 + 1 = -79
1 + 2d + d2 = -79

Factor a perfect square on the left side:
(d + 1)(d + 1) = -79

Can't calculate square root of the right side.

The solution to this equation could not be determined.